Here are 4 ways to split a word into an array of characters. “Split” is the most common and more robust way. But with the addition of ES6, there are more tools in the JS arsenal to play with
I always like to see all the possible ways to solve something because then you can choose the best way for your use case. Also, when you see it pop up in someone’s codebase, you will understand it with ease 👍
const string = 'word'; // Option 1 string.split(''); // Option 2 [...string]; // Option 3 Array.from(string); // Option 4 Object.assign(, string); // Result: // ['w', 'o', 'r', 'd']
Instead of going through the pros and cons of each different way. Let me show you the different scenarios where one is preferred over the other.
If all you’re doing is wanting separate the string by each string character, all of the ways are good and will give you the same result
const string = 'hi there'; const usingSplit = string.split(''); const usingSpread = [...string]; const usingArrayFrom = Array.from(string); const usingObjectAssign = Object.assign(, string); // Result // [ 'h', 'i', ' ', 't', 'h', 'e', 'r', 'e' ]
If you want to split your string by a specific character, then
split is the way to go.
const string = 'split-by-dash'; const usingSplit = string.split('-'); // [ 'split', 'by', 'dash' ]
The other ways are limited by each string character only
const string = 'split-by-dash'; const usingSpread = [...string]; const usingArrayFrom = Array.from(string); const usingObjectAssign = Object.assign(, string); // Result: // [ 's', 'p', 'l', 'i', 't', '-', 'b', 'y', '-', 'd', 'a', 's', 'h' ]
If your strings contain emojis, then
Object.assign might not be the best choice. Let’s see what happens:
const string = 'cake😋'; const usingSplit = string.split(''); const usingObjectAssign = Object.assign(, string); // Result // [ 'c', 'a', 'k', 'e', '�', '�' ]
However, if we use the other ways, it works :
const usingSpread = [...string]; const usingArrayFrom = Array.from(string); // Result // [ 'c', 'a', 'k', 'e', '😋' ]
This is because
split separates characters by UTF-16 code units which are problematic because emoji characters are UTF-8. If we look at our yum emoji
'😋' it’s actually made up of 2 characters NOT 1 as we perceive.
'😋'.length; // 2
This is what’s called grapheme clusters — where the user perceives it as 1 single unit, but under the hood, it’s in fact made up of multiple units. The newer methods
Array.from are better equipped to handle these and will split your string by grapheme clusters
One thing to note
Object.assign is that it doesn’t actually produce a pure array. Let’s start with its definition
The Object.assign() method copies all enumerable own properties from one or more source objects to a target object
The key there is “copies all enumerable own properties”. So what we’re doing here
Object.assign(, string) it copying ALL of our string properties over to our new array. Which means we have an Array PLUS some string methods.
This is more evident if we use the TypeScript Playground. Feel free to copy the code and paste in the playground, where you can hover on the variable to view the types. Since this is just an article, I’ll paste the result here so you can follow along.
const word = 'word'; const usingSplit = string.split(''); const usingSpread = [...string]; const usingArrayFrom = Array.from(string); // Result: // string 👈 Which means it's an Array of strings
However, if we look at the result type of
Object.assign. It doesn’t give us an Array of strings.
const usingObjectAssign = Object.assign(, string); // Result: // never & "string" 👈 which means NOT Array of strings 😱
We can do further check this by accessing a property that should only be available to a
const string = 'string'; const array = ; string.bold; // ✅(method) String.bold(): string array.bold; // ❌Property 'bold' does not exist on type
So that means if I call
bold on our Array, it should tell us this property doesn’t exist. This is what we expect to see:
Array.from('string').bold; // Property 'bold' does not exist on type
BUT, if we call
bold on our supposedly Array created by
Object.assign, it works 😱
Object.assign(, 'string').bold; // (method) String.bold(): string
And this is because
Object.assign copies over ALL the properties over from the original String. Here’s how I’d explain it in non-dev terms. You go to a store to buy a dog. But then store
Object.assign sells you a dog that has dragon wings. This sounds super cool, but this isn’t really a rental friendly pet. Hmm…I don’t think this is my best example. But I think you get my point
Now I don’t think this is a major deal-breaker, cause:
It seems that browsers have some kind of mechanism in place to “safely” do Object.assign(, “string”) and avoid adding the methods of that string to the array.
Thank you @lukeshiru: for sharing this knowledge for me 👏 He also created a TypeScript playground code so you can see > link
@CaptainOrion_:](https://twitter.com/captainorion_/status/1238979904567271425?s=21):_) Turn string into char Array but using map function 🤣
Array.prototype.map.call('word', eachLetter => eachLetter); // ['w', 'o', 'r', 'd']
Array.prototype.slice.call('string') wil do the trick too
@inside.code: Extra info: it’s safer to use the spread operator (second method) rather than
String.prototype.split('') (first method), because
split() doesn’t work with some uncommon characters.
@faerberrr: I had a string that contained special characters like
åæāă etc. When I split them using the
.split('') method and ran
.length, it returned twice the expected value! Switching to the spread operator fixed the problem.